Use basic identities to simplify the expression. cot θ sec θ sin θ
Do you know your identites foremost?
Yeah this one uses the pythagorean identity right
Not exactly, this most likely looks like something that using the reciprocal identities. \[\Large \cot \theta= \frac {\cos \theta}{\sin \theta}\] \[\Large \sec \theta= \frac {1}{\cos \theta} \] \[\Large \csc \theta=\frac{ 1} {\sin \theta} \]
So you just replace the cot and sec with it.
I did that I need help solving it because i got the wrong answer
Ok well substituting, we get \[\Large \frac {\cos \theta}{\sin \theta} \times \frac {1}{\cos \theta} \times \sin \theta\]
|dw:1375057814277:dw| the cos and the sin cancel out and you're left with ?
1 ok thanks that helped could you you help me out with one more ?
Sure, np
Thanks its like the one before Use basic identities to simplify the expression. \[1/ \cot \theta +\sec \sin\]
and the cot is squared
Open a new thread for the question, more help can be awarded
so close this one
Yes,
Oh and tag me @Seadog12
how
press @ then type my name in the comments like how i tagged you ^^
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