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Mathematics 11 Online
OpenStudy (anonymous):

Use basic identities to simplify the expression. cot θ sec θ sin θ

OpenStudy (anonymous):

Do you know your identites foremost?

OpenStudy (anonymous):

Yeah this one uses the pythagorean identity right

OpenStudy (anonymous):

Not exactly, this most likely looks like something that using the reciprocal identities. \[\Large \cot \theta= \frac {\cos \theta}{\sin \theta}\] \[\Large \sec \theta= \frac {1}{\cos \theta} \] \[\Large \csc \theta=\frac{ 1} {\sin \theta} \]

OpenStudy (anonymous):

So you just replace the cot and sec with it.

OpenStudy (anonymous):

I did that I need help solving it because i got the wrong answer

OpenStudy (anonymous):

Ok well substituting, we get \[\Large \frac {\cos \theta}{\sin \theta} \times \frac {1}{\cos \theta} \times \sin \theta\]

OpenStudy (anonymous):

|dw:1375057814277:dw| the cos and the sin cancel out and you're left with ?

OpenStudy (anonymous):

1 ok thanks that helped could you you help me out with one more ?

OpenStudy (anonymous):

Sure, np

OpenStudy (anonymous):

Thanks its like the one before Use basic identities to simplify the expression. \[1/ \cot \theta +\sec \sin\]

OpenStudy (anonymous):

and the cot is squared

OpenStudy (anonymous):

Open a new thread for the question, more help can be awarded

OpenStudy (anonymous):

so close this one

OpenStudy (anonymous):

Yes,

OpenStudy (anonymous):

Oh and tag me @Seadog12

OpenStudy (anonymous):

how

OpenStudy (anonymous):

press @ then type my name in the comments like how i tagged you ^^

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