Question

6z3–27z2+12z

Answer 1

What are you trying to do here, simplify? If so, we want to find a factor that can be pulled out of each term

Answer 2

6z^3 - 27z^2 + 12z

Answer 3

3z can be pulled out, I got this so far

Answer 4

3z(2z - 9z + 4)

Answer 5

Thats right, but you're missing your z^2 in the first term inside the parentheses

Answer 6

oh yeah

Answer 7

3z(2z-3)(z+1)?

Answer 8

you cant go further then 3z(2z^2 - 9z + 4) so we need to solve this like this:
\[3z(2z^2 - 9z + 4)\]divide both sides by 3
\[z(2z^2-9z+4)\]
solve each separetely split into two equations
\[z=0 \]or\[2z^2-9z+4=0\] can you continue from here?

Answer 9

@Sabot3 No, if you multiply out your simplification it doesn't match the original, so you factored incorrectly.

Answer 10

working on it now