Question

solve for x: (x-4)^2=2

Answer 1

expand:
\[(a-b)^2 = a^2-2ab+b^2\]

Answer 2

9?

Answer 3

well expand first, what do you get?

Answer 4

(1-4)^2=1^2-2(1)(4)+4^2..?

Answer 5

\[(x-4)^2 = x^2-8x+16=2\]\[x^2-8x+14=0\]Now just use the discriminant formula.

Answer 6

whats the discriminant formula??

Answer 7

\[D=b^2-4ac\]\[x_1=\frac{-b-\sqrt{D}}{2a}\]\[x_2=\frac{-b+\sqrt{D}}{2a}\]

Answer 8

so quadratic pretty much

Answer 9

yea

Answer 10

\[\large (x-4)^2 = 2\]\[\large \sqrt{(x-4)^2} = \pm \sqrt{2}\]\[\large x-4 = \pm\sqrt{2}\]\[\large x= 4 \pm \sqrt{2}\]

Answer 11

:P

Answer 12

thats not one of the options

Answer 13

you'll have 2 answers. one positive,one negative.

Answer 14

yeah none of the options look like that though there all written with the positive or negative sign but none of them are that

Answer 15

Just split it up then....

Answer 16

4 + ... , 4 - ...

Answer 17

...oops nevermind it is an option i was looking at a different question..