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OpenStudy (anonymous):

Calculus Trajectory Problem (comment below)

OpenStudy (anonymous):

r(t) = <3cost,5sint,4cost> for 0 ≤ t ≤ T suppose the circular path of this function is to be traversed at a constant speed of 15m/s. Find the description of the trajectory. On what interval of 0 ≤ t ≤ T is the circle traversed once? Before this question the previous question was the same but find the speed using \[S(t) = u'(t)\sqrt{f'(u(t))^2+g'(u(t))^{2}+h'(u(t))}\] u(t) = 1 u'(t) = dt in this case I solved that and found that the speed came out to be 5. Now I don't know how to solve for the time interval

OpenStudy (anonymous):

In the previous problem time was defined between \[0 \le t \le 2π\]

OpenStudy (anonymous):

Also made a mistake above.. u(t) = t u'(t) = 1

OpenStudy (anonymous):

@Charollete r(t) is an ellipsoid?

OpenStudy (anonymous):

I believe so

OpenStudy (anonymous):

@sarahusher @FutureMathProfessor Can you guys help?

OpenStudy (anonymous):

@primeralph any idea?

OpenStudy (primeralph):

Still need help?

OpenStudy (anonymous):

Yea

OpenStudy (anonymous):

Any idea how I can find the time interval with constant speed of 15ms?

OpenStudy (primeralph):

Equate S to 15.

OpenStudy (primeralph):

All you have to do is find the time at which r(t+T) = r(t) = r(0).

OpenStudy (primeralph):

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