A cell and its nucleus both have a spherical shape; the nucleus is 1 µm diameter and the cell is 15 um in diameter. ( Note: the formula for the surface area is 4πr2, and the formula for the volume of a sphere is : 4/3πr3, where r is the radius of the sphere and the π is 3.1416.)

After calculating the cellular/ nuclear volume, how many times greater would the cell/nuclear ratio be if the cell were to triple its diameter (assuming the nucleus would remain the same size)?

Question

A cell and its nucleus both have a spherical shape; the nucleus is 1 µm diameter and the cell is 15 um in diameter. ( Note: the formula for the surface area is 4πr2, and the formula for the volume of a sphere is : 4/3πr3, where r is the radius of the sphere and the π is 3.1416.)

After calculating the cellular/ nuclear volume, how many times greater would the cell/nuclear ratio be if the cell were to triple its diameter (assuming the nucleus would remain the same size)?

anonymous · Answer

just put the values in the formula and calculate it u will find the ratio

aaronq · Answer

V= (4/3)*π*r^3=(4/3)*π*(d/2)^3

so first calculate the volume of both as they are: 
d=1 micrometer and 10 micrometers.  (use: V=(4/3)*π*(d/2)^3)

-> find the ratio, V(nucleus)/V(cell)

then, if the cell triples diameter, so 10*3 =30 micrometers.

find it's volume, again find the ratio, V(nucleus)/V(cell), with this new value.

now divide the second ratio by the first ratio.

second ratio/first ratio= how many time greater the ratio would be if d of cell was x3.