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Mathematics 14 Online
OpenStudy (anonymous):

Can someone please show me how in the world do I solve: P = A - Prt

OpenStudy (texaschic101):

are you solving for a certain letter ?

OpenStudy (anonymous):

yes for P

OpenStudy (ivancsc1996):

You pass al the P's to a side, then you factorize and finally you divide:\[P+Prt=A \rightarrow P(1+rt)=A \rightarrow P=\frac{ A }{ 1+rt }\]

OpenStudy (anonymous):

I get the passing the Prt to the left side....lost after that...not sure how to factorize

OpenStudy (anonymous):

I am lost on the factorize part

OpenStudy (ivancsc1996):

Ok when you sum two terms that have similar multiplications you can do this:\[xy+xz=x(y+z)\] See?

OpenStudy (ivancsc1996):

In your case, x=P, y=1 and z=rt

OpenStudy (anonymous):

ok...getting it but not 100% there

OpenStudy (ivancsc1996):

Do you know the distributive property of multiplication?

OpenStudy (anonymous):

yes......got confused about where the 1 came from T + Txy would be T(1 + xy) right?

OpenStudy (anonymous):

@openstudy276 that's correct. T + Txy = T(1 + xy). You "Factor" out the T from each. Similarly you factor out the P from P + Prt to get P(1 + rt). When you expand P(1 + rt), using the distributive property you get: P(1) + P(rt) = P + Prt. You're back to where you started from! This means that P( 1 + rt) is the correct factortisation. Now divide both sides by 1 + rt to isolate P from the rest of the equation and you're done.

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