Question

HELP: evaluating limits to infinity by dividing x
(ATTACHED BELOW)

Answer 1

i got 3/5 but it's wrong.

Answer 2

@kropot72 do you know this?

Answer 3

@satellite73 any ideas?

Answer 4

0

Answer 5

if the denominator grows bigger than the numerator, then the limit is 0

Answer 6

oh so we don;t need to divide by x? or do anything to it?

Answer 7

nope!

Answer 8

thanks! :) @hihihii

Answer 9

no problem!

Answer 10

\[\lim_{x \rightarrow \infty} \dfrac{3x + 2}{3x^2 - 5x + 8}\]
\[ =\lim_{x \rightarrow \infty} \dfrac{ x^2 \left( \frac{3}{x} + \frac{2}{x^2} \right) } {x^2 \left( 3 - \frac{5}{x} + \frac{8}{x^2} \right) }\]
\[ = \lim_{x \rightarrow \infty} \dfrac{ \frac{3}{x} + \frac{2}{x^2} } { 3 - \frac{5}{x} + \frac{8}{x^2} } \]
\[ = \dfrac{ 0 + 0} { 3 - 0 + 0 } \]
\(= 0\)

Answer 11

thanks u @mathstudent55

Answer 12

You're welcome.