What is the slope of the line that passes through the given points? (6, 2) and (7, 4) a.-2 b.1/2 c.-1/2 d. 2
do you know the slope formula point slope formula
no.
what formulas do you know
wait yes. y-y1=m(x-x1)
technically the the whole idea is this |dw:1375077654535:dw|
did i confuse you or ....
no, i follow.
is it d?
well can you show me your work how you came to your answer
2-4=m(6-7) -2=m(-1) (-2)(-1) 2
you are supposed to get the slope first you are using the point slope formula
You have two points, so you need the two-point equation of a line: A line that passes through points \((x_1, ~y_1)\) and \((x_2, ~y_2) \) has the equation: \(y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1} (x - x_1)\) Use \( (6, ~2) \) as \( (x_1, ~y_1) \) and \( (7, ~4) \) as \( (x_2, ~y_2) \). Plug in all 4 values into the two-point equation above and simplify.
the slope formula is y - y1 ----- = m x- x1
|dw:1375078882493:dw|
i'm confused. i tried that all together and got two again.
lol you might be correct :P i haven't tried it out actually lol
looks good :P
okay, thank you!
\(y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1} (x - x_1) \) \(y - 2 = \dfrac{4 - 2}{7 - 6} (x - 6) \) \(y - 2 = \dfrac{2}{7} (x - 6) \) \(y - 2 = 2(x - 6) \) \(y - 2 = 2x - 12\) \(y = 2x - 10\)
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