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Mathematics 9 Online
OpenStudy (anonymous):

https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/729016,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/surface_area_and_volume/mc042-1.jpg What is the surface area of the cone?

OpenStudy (mathstudent55):

\(SA_{cone} = A_{lateral} + A_{base} \) \(A_{lateral} = \pi r h_{slant} \) \(A_{base} = \pi r^2 \)

OpenStudy (mathstudent55):

|dw:1375078001384:dw|

OpenStudy (anonymous):

@Math81 i got 120 is that correct

OpenStudy (mathstudent55):

\(SA_{cone} = A_{lateral} + A_{base} \) \(SA_{cone} = \pi r h_{slant} + \pi r^2 \) First we need the slant height.

OpenStudy (mathstudent55):

|dw:1375117362374:dw| The slant height is 13 cm.

OpenStudy (mathstudent55):

\(SA_{cone} = \pi r h_{slant} + \pi r^2\) \(SA_{cone} = \pi (5 ~cm)(13 ~cm) + \pi (5 ~cm)^2 \) \(SA_{cone} = 65 \pi ~cm^2 + 25 \pi ~cm^2 \) \(SA_{cone} = 90 \pi ~cm^2 \approx 282.74 ~cm^2\)

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