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Mathematics 7 Online
OpenStudy (anonymous):

Determine the slope of the secant line for the curve defined by the equation: (attached below)

OpenStudy (anonymous):

OpenStudy (anonymous):

The slope of the secant line is basically the average rate of change from \(\bf x_0\) to \(\bf x_1\). This is given by:\[\bf m_{secant}=A.R.C.H|_{x_0}^{x_1}=\frac{ f(x_1)-f(x_0) }{ x_1-x_0 }\]

OpenStudy (anonymous):

@mathcalculus Can you do that?

OpenStudy (anonymous):

is that like the differentiation but in other terms?

OpenStudy (anonymous):

@genius12

OpenStudy (anonymous):

is it = to 1?

OpenStudy (anonymous):

do we substitute just for it?

OpenStudy (anonymous):

can we solve this together? @genius12

OpenStudy (anonymous):

im stuck.

OpenStudy (anonymous):

Ok I will solve step by step. Firstly, you should realise that this is essentially the slope formula which is:\[\bf m=\frac{ y_2-y_1 }{ x_2-x_1 }\]You remember that formula? @mathstudent55

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that's the formula to find the slope .

OpenStudy (anonymous):

are you there?

OpenStudy (anonymous):

Well that what this essentially is! It's the slope, of the secant line, and the secant line is the line that connects the two points on the graph when x = -5 to when x = -6. I'll draw the graph and show to you:|dw:1375078386992:dw|

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