Question

DERIVATIVES:
(attached below)

Answer 1

Now that's one that confuses me, too, lol x_x Not even sure what you're supposed to do with it. Curious to see what other people say.

Answer 2

Oh, wait, I think it just wants the function?

Answer 3

invite people.

Answer 4

we can all use the help.

Answer 5

Can We Use L-hospitals Rule ?

Answer 6

Don't even know how to do that :P But the only thing I would be able to do is recognize that the function is x^(-3.25) and go from there. But that;d be cheating I think. And nah, l-hopitals rule is above his class.

Answer 7

i don't know. it's a derivative question.

Answer 8

L'hopitals rule is a calc II thing, so not much to worry about for yourself, lol.

Answer 9

If I were you i would use hopital phenomenal .

Answer 10

yeah, no no hospital rule.

Answer 11

Hehe, hospital rule.

Answer 12

differentiate both numerator n denominator with respect to h
u got ur answer n put h =0

Answer 13

I was thinking the same as Psyman mentioned that the original function is
y=x^(-3.25)
dy/dx=-3.25x^(-2.25)

i guess in order to evaluate the limit Binomial expansion is required

Answer 14

simple l hopital rule wud do in this case

Answer 15

I was thinking the expansion wasn't what the question really wanted, though.

Answer 16

He is Just Newbie in the calculus I think He dont know L'Hôpital's rule !

Answer 17

Yeah, he hasn't seen l'hopitals rule if he's just now doing this.

Answer 18

SIGN: people who know this only.

Answer 19

\[\frac{ dx^p }{ dx }=\lim_{h \rightarrow 0}\frac{ (x+h)^p-x^p }{ h }=px^{p-1}\]
And in this case p=-3.125

Answer 20

Sorry, p=-3.25

Answer 21

Then the solution:\[-3.25x^{-4.25}\]

Answer 22

this is as mentioned above the derivative of the function
\[\Large y=x^{-3.25}\]
using the power rule of derivative which states
if
\[\Large y=x^n\]
\[\Large \frac{dy}{dx}=nx^{n-1}\]

here n=3.25 just appply the power rule formula
\[\Large \frac{dy}{dx}=-3.25x^{(-3.25-1)}\]
\[\Huge \frac{dy}{dx}=-3.25x^{-4.25}\]

Answer 23

Yeah, more of just a knowledge of what the power rule for a derivative is and where within that difference quotient the original function actually is. In the end, it's the start of getting used to nx^(n-1) for derivatives :P