Question

the domain of f(x)=logbase2 (x+3)/x^2+3x+2 is

Answer 1

You need to find all values of x such that x>0. Sothat means factoring the denominator and solving for x, but also solving for x in the numerator since you cannot have 0 at all inside of a log.

Answer 2

log of negative is not allowed so
(x+3)/x^2+3x+2 should be greater than 0
also both numerator n denominator should be positive or both negative
it wud be quite easy to solve on paper

Answer 3

just put x+3>0 also 3x+2>0 for one case take the intersection of values
and put x+3<0 and 3x+2<0 n take intersection

Answer 4

\[\log _{2} \frac{ x+3 }{ (x+1)(x+2) }\]use base change and you can do it

Answer 5

can anybody plz solve it

Answer 6

your x gotta be greater than 2 and 3 so basically domain is x>3

Answer 7

x>-3 and x>-2/3 so in first case x >-2/3
in second case
x<-3 and x <-2/3 so we have x <-3
so answer is (-infinity to -3) union (-2/3 to infinity )

Answer 8

no chandan this is not the answer.......this was an iit question

Answer 9

even I done this but this is wrong

Answer 10

let me solve this on paper

Answer 11

ok

Answer 12

i got the same answer can u tell me what is the answer??? then we will see

Answer 13

1.r-{-1,-2}
2.(-2,+infinity)
3.r-{-1,-2,-3}
4.(-3,+infinity)-{-1,-2}