Question

if logbase12 27 =a then the value of logbase6 16 is

Answer 1

Remember that you can change a log to any base you want, using this rule:
log[base b](a) = log[base c](a) / log[base c](b)

So here you have
log[base 12](27) = a
log[base 6](27) / log[base 6](12) = a

Now we need to get "log[base 6](16)" somewhere out of this:
log[base 6](27) = a log[base 6](12)
log[base 6](27) = a log[base 6](4*3)
log[base 6](27) = a ( log[base 6](4) + log[base 6](3) )
log[base 6](27) = a ( log[base 6](16^(1/2)) + log[base 6](3) )
log[base 6](27) = a ( (1/2)log[base 6](16) + log[base 6](3) )

Now just solve this so that "log[base 6](16)" is on one side.

Answer 2

@23ayesha1994 no problem.

Answer 3

also 27 = 3^3
you can get answer in terms of "a" and log_base6 (3)

Answer 4

no imtiaz thankz for help

Answer 5

ok so i need help from u can u help me?

Answer 6

ya sure

Answer 7

http://openstudy.com/updates/51f61d72e4b00daf471cacaa
in this q