Find the difference quotient for f(x)=12/x^2 Any help is greatly appreciated.
\[f(x)=\frac{ 12 }{ x^2 } \]
Im still struggling with this one I just dont get it please help!
\[\frac{\frac{12}{(x+h)^2}-\frac{12}{x^2}}{h}\]
:) that is exactly where I am stuck.....
\[\frac{\frac{12x^2}{(x+h)^2*x^2}-\frac{12(x+h)^2}{(x+h)^2x^2}}{h}\]= \[\frac{12x^2-(x^2+2xh+h^2)}{h(x+h)^2x^2}\]= \[\frac{11x^2-2xh-h^2}{h(x+h)^2x^2}\]
do you need to take the limit?
woops sec I messed up
interesting so you did multiplied side by side.... and I think I need the limit. Which I believe is the simplest form?
\[\frac{12x^2-12(x^2+2xh+h^2)}{hx^2(x+h)^2}\]= \[\frac{12x^2-12x^2-24xh-12h^2}{hx^2(x+h)^2}\]= \[\frac{-24xh-12h^2}{hx^2(x+h)^2}\]= \[\frac{-24-12h}{x^2(x+h)^2}\]
when I say limit, I mean when h goes to infinity. Is this for calculus or algebra?
Alg
I mean 0 not infinity
ok well then you don't want the limit im guessing.
this is the form you want.
you are actually doing calculus you just don't know it yet:)
God i can only imagine the rest....
either way I chose this path so better get used to it :) one last question... Is this the simplest form I am looking at other exmaples and they're nice and neat
Out of all this one was vicious
\[\frac{-24x-12h}{x^2(x+h)^2}\]
that's the final
K K thank you so much I will try to sort the others by myself... :) looks like another all nighter. Thanks again
yeah there is not much else you can do to it http://www.wolframalpha.com/input/?i=simplify++%28%E2%88%9224x%E2%88%9212h+%29%2F%28x%5E2*%28x%2Bh%29%5E2%29++++
nice. Will check this site little bit more.
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