Question

if 7log base a 16/15+5log base a 25/24 +3log base a 81/80=8 then a is

Answer 1

=
log((16/15)^7)+log((25/24)^5)+log((81/80)^3)=8
a^[log((16/15)^7)+log((25/24)^5)+log((81/80)^3)]=a^8
a^log((16/15)^7) * a^log((25/24)^5) * a^log((81/80)^3=a^8
(16/15)^7 * (25/24)^5 * (81/80)^3 = a^8
a^8 = 2
\[a=\sqrt[8]{2}\]

Answer 2

thankz

Answer 3

np, sorry for typos. I think I fixed them all

Answer 4

do you understand all the steps?

Answer 5

properties used

a*log(b) = log(b^a)
and
a^b*a^c = a^(b+c)
and
a^log_a(x) = x

Answer 6

I think technically
\[a=\pm \sqrt[8]{2}\]