Question

An acute angle θ is in a right triangle with cos θ = five sixths. What is the value of sec θ?

Answer 1

sec = 1/cos fo just find the reciprocal of cos

Answer 2

square root of eleven divided by six

five divided by square root of eleven

six fifths

eleven divided by five

Answer 3

which one?

Answer 4

well look at it this way



\[\sec ( \theta) = \frac{1}{\cos(\theta)}\]

are you sure you have the correct information, the ratio is cos and you need to find sec..?

Answer 5

Yes I am sure that its one of them

Answer 6

because if you know cos

\[\cos(\theta) = \frac{5}{6} \]

then

\[\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{1}{\frac{5}{6}}\]

just simplify

Answer 7

So the answer is 5/6?

Answer 8

nope the rule for dividing by a fraction is take the reciprocal and multiply

Answer 9

so its 6/5 right?

Answer 10

so you get

\[\frac{1}{\frac{5}{6}} = 1 \times \frac{6}{5} \]

Answer 11

correct

Answer 12

Thank you for your help

Answer 13

An acute angle θ is in a right triangle with sin θ = seven eighths. What is the value of cot θ?

Answer 14

draw a triangle and then use the a^2+b^2 = c^2 to find the missing value.