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Mathematics 15 Online
OpenStudy (anonymous):

cos(sinx)=1 ...find all the solutions...help please...

OpenStudy (psymon):

Well, we can start off with knowing when does cosine = 1?

OpenStudy (anonymous):

when...uhm...i..dont know...

OpenStudy (anonymous):

oh wait

OpenStudy (anonymous):

90 degrees

OpenStudy (anonymous):

270 degrees too

OpenStudy (anonymous):

in radians?

OpenStudy (psymon):

Not for cosine, no. Thats when sin is 1 and -1.

OpenStudy (anonymous):

ok :/

OpenStudy (anonymous):

but cosine is 0 on both...:/

OpenStudy (psymon):

Ah, sorry, my brain is reversing it

OpenStudy (anonymous):

so i had it right?

OpenStudy (psymon):

Whoa, whoa, we want to know when cosine = 1, not when itequals 0. Thats whatI wastrying to ask.

OpenStudy (anonymous):

ok..so cosine equals one at...pi and zero

OpenStudy (psymon):

Exactly. So cos(pi) and cos(0) = 1, which means you haveto find values for sin x where it'lll equal pi or 0.

OpenStudy (anonymous):

how do i do that...

OpenStudy (psymon):

The same way you knew where cosine was 0 :3. Its just this time we want to know where sin is 0 or sin is pi.

OpenStudy (anonymous):

so 90 and 270? degrees...not radians

OpenStudy (anonymous):

i looked at the unit circle...idk

OpenStudy (psymon):

Well, Id assume itd want the answer in radians. But yes, 90 degrees and 270 degrees is correct. Which would be pi/2 and 3pi/2. As for the second part, sin is never equal to pi. The range of the sin function is [-1,1], so finding sin x = pi is impossible.

OpenStudy (anonymous):

ok...well i looked at the actual answer and i dont think its right :/ or i just still dont follow :/

OpenStudy (psymon):

Wow, my brain is reversing it. Rob will correct me.

OpenStudy (anonymous):

npi, n=0, pos/neg 1,and 2

OpenStudy (anonymous):

x = 0 by inspection. Sin[0]=0 Cos[0]=1

OpenStudy (anonymous):

what

OpenStudy (psymon):

We need sin x to equal 0, that way we can say cos(0) = 1. Sin x is 0 at the angles 0 and pi. So those two should be your answer. *hits head so it'll work*

OpenStudy (anonymous):

but then how is one and two the answer..

OpenStudy (psymon):

I do not see how they could be with the given information.

OpenStudy (anonymous):

so i should contact my teacher...eh?

OpenStudy (psymon):

Well, think of it this way, if x = 1 or 2, then sin(1) and sin(2) have to = 0.

OpenStudy (anonymous):

A plot is attached.

OpenStudy (psymon):

That graph would include pi as well, it just starts to cut off there.

OpenStudy (anonymous):

that didnt help me...but thank you @robtobey

OpenStudy (psymon):

But no, I see no way it can be 1 or 2 personally. Can you see why sinx onsode the parenthesis would have to be 0?

OpenStudy (psymon):

*inside

OpenStudy (anonymous):

no not really :/

OpenStudy (psymon):

Alright. Lets pretend sin x = y Therefore cos(y) = 1 This is true when y = 0 So if y must be 0 and sin x = y, then we need to have sin x = 0. Sin x = 0 when x is 0 or pi.

OpenStudy (anonymous):

ok...quick question...do you know that cos(0)is one like by memory?

OpenStudy (psymon):

Pretty much. Its amazing how much Ive had to use that unit circle. For other random units like 5pi/6 or something, I have a way that helps me remember them.

OpenStudy (anonymous):

alright. I think I understand the point youre trying to make/have made. thank you

OpenStudy (psymon):

Yeah, sure. And there is a way to remember the unit circle. Apart from the x axis and y axis, the values for sin and cos have a pattern that can be remembered.

OpenStudy (anonymous):

alright, thank you

OpenStudy (psymon):

Good luck :3

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