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Chemistry 16 Online
OpenStudy (anonymous):

The specific heat of a substance is 2.91 J/g·°C. If given 10.4 grams of the substance and if the temperature of the substance increases by 26 degrees Celsius, how much heat is absorbed? a) 790 kJ b) 7.9 x 102 kJ c) 7.9 x 10−1 kJ d) 0.79 J

OpenStudy (aaronq):

use the formula, q=m*C*dT

OpenStudy (anonymous):

I did and got 786.864, but I am not sure how I should convert that to get one of the provided answers

OpenStudy (aaronq):

what units is your value in?

OpenStudy (anonymous):

J because I didn't convert anything. I just did (2.91)(10.4)(26)=786.864

OpenStudy (aaronq):

look at the values given, what units are they in?

OpenStudy (anonymous):

kJ and one is in J so will I have to convert J to kJ

OpenStudy (aaronq):

yep, do that and compare them

OpenStudy (anonymous):

I got .786 Kj so would the answer be 7.9 x 10−1 kJ

OpenStudy (aaronq):

yep, you got it.

OpenStudy (anonymous):

Thanks so much!!

OpenStudy (aaronq):

no problem, dude !

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