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The specific heat of a substance is 2.91 J/g·°C. If given 10.4 grams of the substance and if the temperature of the substance increases by 26 degrees Celsius, how much heat is absorbed? a) 790 kJ b) 7.9 x 102 kJ c) 7.9 x 10−1 kJ d) 0.79 J
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use the formula, q=m*C*dT
I did and got 786.864, but I am not sure how I should convert that to get one of the provided answers
what units is your value in?
J because I didn't convert anything. I just did (2.91)(10.4)(26)=786.864
look at the values given, what units are they in?
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kJ and one is in J so will I have to convert J to kJ
yep, do that and compare them
I got .786 Kj so would the answer be 7.9 x 10−1 kJ
yep, you got it.
Thanks so much!!
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no problem, dude !
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