Question

PLEASE PLEASE PLEASE HELP Anyone MEDAL AND FAN!!!
A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side lengths equal to 16.35 in. Find the area of the second octagon.
A. 461.60 in2
B. 882.9 in2
C. 717.06 in2
D. 642.66 in2

Answer 1

@jdoe0001

Answer 2

ratio of the one SQUARED will correspond to the ratio of the area of the other, thus
small one has a side length of 10.9, and the bigger one has a side length of 16.35
thus
\(\bf \cfrac{16.35^2}{10.9^2}=\cfrac{x}{392.4}\)

Answer 3

solve for "x"

Answer 4

588.6

Answer 5

you need to use the SQUARED form of the ratio of the side length, that is \(\bf \cfrac{16.35^2}{10.9^2}\)

Answer 6

588.6 will be the result of the non-squared version

Answer 7

but how will you make that squared ?

Answer 8

well, what's \(\bf 16.35^2\)?

Answer 9

267.3225

Answer 10

so you use that, the same goes with \(\bf 10.9^2 = 118.81\)

Answer 11

B

Answer 12

:)

Answer 13

thank you verymuch

Answer 14

yw