Suppose a triangle has sides a, b, and c, and that a2 + b2 < c2. Let be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply.
\[A. cos \theta\] <0 B. the triangle is a right triangle C. the triangle is not a right triangle \[D. \theta \] is an obtuse angle help me please
I don't know
I need more help I do not understand
use the cosine rule
cos C = (a^2 + b^2 - c^2)/(2ab) we knowed that a^2 + b^2 < c^2 obviously, the numerator be negative and the denominator is positive. cos C = -/+ cos C = - so, <C is in the 2nd quadrant (more than 90 degrees) finally, it is an obtuse triangle
so the answer is only D
wait, is the theta the measure of the angle opposite the side of length c ?
check the original question.... let .?.. (is it theta)
you see the picture
aha, i thought that is the theta :) you just miss it after you type let ........
cos C = cos θ like i said above : cos C = - it means that cos θ < 0 (A is correct, and D is correct too)
Suppose a triangle has sides a, b, and c, and that a2 + b2 < c2. Let be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply. A. The triangle is not a right triangle. B. The triangle is a right triangle. C. cos < 0 D. is an acute angle.
Join our real-time social learning platform and learn together with your friends!