Question

what are the foci of the graph

Answer 1

\(\bf \cfrac{x^2}{25}-\cfrac{y^2}{200}=1 \ \ ?\)

Answer 2

right, I just dunno of the 1st denominator is 25 or not :/

Answer 3

what you have typed out is correct

Answer 4

\(\bf \cfrac{x^2}{25}-\cfrac{y^2}{200}=1\\\cfrac{(x-h)^2}{a^2}-\cfrac{(y-k)^2}{b^2}=1\\
\text{distance from the center to either focus is "c"}\\
c^2 = a^2 + b^2 \implies c = \sqrt{a^2 + b^2}
\)

Answer 5

(+/-5,0)

Answer 6

well, the root didn't give me that :/

Answer 7

keep in mind that is \(\bf \sqrt{a^2 + b^2} \) not \(\bf \sqrt{a^2 - b^2}\)

Answer 8

\(\bf \cfrac{x^2}{25}-\cfrac{y^2}{200}=1\\
\cfrac{(x-h)^2}{a^2}-\cfrac{(y-k)^2}{b^2}=1\)

what would be the "a" component in your equation?
which one is the "b" component?