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Mathematics 6 Online
OpenStudy (anonymous):

what are the foci of the graph

OpenStudy (anonymous):

|dw:1375123230906:dw|

OpenStudy (jdoe0001):

\(\bf \cfrac{x^2}{25}-\cfrac{y^2}{200}=1 \ \ ?\)

OpenStudy (jdoe0001):

right, I just dunno of the 1st denominator is 25 or not :/

OpenStudy (anonymous):

what you have typed out is correct

OpenStudy (jdoe0001):

\(\bf \cfrac{x^2}{25}-\cfrac{y^2}{200}=1\\\cfrac{(x-h)^2}{a^2}-\cfrac{(y-k)^2}{b^2}=1\\ \text{distance from the center to either focus is "c"}\\ c^2 = a^2 + b^2 \implies c = \sqrt{a^2 + b^2} \)

OpenStudy (anonymous):

(+/-5,0)

OpenStudy (jdoe0001):

well, the root didn't give me that :/

OpenStudy (jdoe0001):

keep in mind that is \(\bf \sqrt{a^2 + b^2} \) not \(\bf \sqrt{a^2 - b^2}\)

OpenStudy (anonymous):

|dw:1375124724671:dw|

OpenStudy (jdoe0001):

\(\bf \cfrac{x^2}{25}-\cfrac{y^2}{200}=1\\ \cfrac{(x-h)^2}{a^2}-\cfrac{(y-k)^2}{b^2}=1\) what would be the "a" component in your equation? which one is the "b" component?

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