The volume of a cube is less than 25, and the length of one of its edges is a positive integer. what is the largest possible value for the total area of the six faces?
if the edge has to be a positive integer along with the volume being less than 25, what are your choices for edge length? which is largest? Now that you know the edge length, you can compute the area of one face of the cube and then multiply that by 6 to get the total surface area.
(A) 1 (B) 6 (C) 24 (D) 54 (E) 150
i dont really understand what youre saying
if the cube has an edge length of 1, then the volume is \[1^{3}=1\] if the edge is length 2 then the volume is \[2^{3}=8\]if the edge length is 3 then the volume is \[3^{3}=27\] Need I go on?
no thank you ..
does it make sense?
kind of, not really...
cube implies all the sides are the same. the volume of a cube is length cubed. in your problem, the length has to be a positive integer: 1, 2, 3, ... but we know that the volume is less than 25. Which side lengths will result in cube volumes that are less than 25?
2?
i got it ..thank u
which choice? just want to make sure you get it right.
c
very good!!! Nice job!
thanks for ur help
you're welcome!
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