Question

Evaluate ∫ 100 ^e-0.01x dx

Answer 1

let u = .01x, du = .01dx.

Answer 2

For clarification, is this your question?
\[\int\limits_{}^{}100^{(e-0.01x)}dx\]

Answer 3

yes

Answer 4

Okie dokie, first step would be to use the rules of exponents to separate the integral into \[\int\limits_{}^{}100^{(e-0.01x)}dx = \int\limits_{}^{}(100^e \times100^{-0.01x})dx=100^e \int\limits_{}^{}100^{-0.01x}dx\]
Try solving it from here.

Hint: rewrite 100 as a power of 10 and -0.01 as a fraction and see what ya get.