Question

find A and B.. Division... :/
(attached below)

Answer 1

this is a little bit much tricky.

Answer 2

its a precursor to the limit definition of a derivative

Answer 3

\[\frac{\frac{1}{g(x+h)}-\frac1{g(x)}}{h}\]
\[\frac{\frac{g(x)-g(x+h)}{g(x+h)~g(x)}}{h}\]
\[\frac{g(x)-g(x+h)}{h[g(x+h)~g(x)]}\]

Answer 4

@amistre64

Answer 5

let g(x) = x+5, the setup is pretty simple to follow from there

Answer 6

i have it set up but the denominators are a problem for me.

Answer 7

don't they need to have the same denominator in order to add or subtract. in this case, subtract.

Answer 8

multiply 15 and 15+h across, but thats just specifics

Answer 9

\[\frac ab+\frac nm=\frac{am+bn}{bm}\]

Answer 10

\[\Large \frac{\frac{1}{g(x+h)}-\frac1{g(x)}}{h}=\frac{\frac{g(x)-g(x+h)}{g(x+h)~g(x)}}{h}\]

Answer 11

isnt it 50+5h

Answer 12

if you leave the specifics till the end, this goes simpler

Answer 13

\[\Large \frac{\frac{1}{g(x+h)}-\frac1{g(x)}}{h}\]
\[\Large \frac{\frac{g(x)-g(x+h)}{g(x+h)~g(x)}}{h}\]
\[\Large \frac{g(x)-g(x+h)}{h({g(x+h)~g(x)})}\]
--------------------------------------
\[\Large g(x)=x+5\]
\[\Large \frac{x+5-(x+5+h)}{h({x+5+h)(x+5)}}\]
\[\Large \frac{x+5-x-5-h}{h({x+5+h)(x+5)}}\]
\[\Large \frac{-\cancel{h}}{\cancel{h}({x+5+h)(x+5)}}\]
\[\Large \frac{-1}{({x+5+h)(x+5)}}\]
let x=10

Answer 14

i didnt add different denominators ... but whatever

Answer 15

i didn't say that @amistre64

Answer 16

lol, then who was it?

Answer 17

@MatthewH any ideaS?

Answer 18

\[\frac ab +\frac nm = some~number~k\]
\[\frac {ab}b +\frac {bn}m = b~k\]
\[\frac {amb}b +\frac {bnm}m = bm~k\]
\[am\frac {b}b +bn\frac {m}m = bm~k\]
\[am +bn = bm~k\]
\[\frac{am +bn}{bm} =k\]
therefore, since k=k we have
\[\frac ab+\frac nm=\frac{am +bn}{bm}\]

Answer 19

what does (15+h) times (15) equal?

Answer 20

225+15h

Answer 21

yes, now multiply the denominators over, crosswise, to the numerators to adjust the tops

Answer 22

can you show me this step by step with the exact numbers? not by a b n it confuses me more.

Answer 23

okay is this correct so far for the numerator? : 1/(15+h) -1/15

Answer 24

@amistre64

Answer 25

@pgpilot326 is this correct so far?

Answer 26

i need to find a and b but im not sure what to do with the denominators in the numerator

Answer 27

@dan815 would u be able to help me out