Question about finding the molecular weight of unknown. I have volume of 8.4mL NaOH with molarity of .120 and mass of unknown is .19g. I'm having trouble setting up the equation to find the mol. weight. Would it be .19 x .0084 divided by .120? Which would make answer come out to be .0133 mol wt.?

Question

aaronq · Answer

did you perform a titration? What other details can you provide?

anonymous · Answer

Yes, I performed a titration. The values I have listed were determined from a previous experiment.

aaronq · Answer

do you know if the substance was a strong acid or a weak acid? was it monoprotic or diprotic?

anonymous · Answer

I don't know if it was strong or weak. It was an unknown.

anonymous · Answer

I've never even heard of those other terms. lol!

aaronq · Answer

haha okay, well with this info " 8.4mL NaOH with molarity of .120", you can find how many moles of OH- you used. 

Molarity=moles of solute/L of solution

Then, you can use the volume of acid you titrated, grams, and moles equivalent to find the molar mass.