Question

cos(theta)-tan(theta)cos(thetha)=0

Answer 1

How do you find the values of this problem?

Answer 2

\[\tan(\Theta) = \frac{ \sin(\Theta) }{ \cos(\Theta) }\]

just substitute that back for tan(theta) and simplify

Answer 3

ok i got cos(theta)-(sin(theta)/cos(theta))cos(theta)=0
cos(theta)-sin(theta)=0 now how do i find the values, cause the answers are
a. 0, pi/4, pi, 5pi/4
b.pi/4, 5pi/4
c.pi/2, 3pi/4, 3pi/2, 7pi/4
d. pi/2, 7pi/6, 3pi/2, 11pi/6

Answer 4

You know what I should have done.... factor the cos(theta)

so this is easier to solve \[\cos(\Theta) [ 1 - \tan(\Theta)] = 0\]

Answer 5

so now solve for \[\cos(\Theta) = 0\]

and \[\tan(\Theta) = -1 \]

Answer 6

so it would be c for my answer from the above choices listed?

Answer 7

yes

Answer 8

i submitted the answer and it was wrong, the correct answer was b but i dont understand how that is, because choice c actually makes sense.

Answer 9

Oh no! I missed a - sign

it should have been

\[1- \tan(\Theta) = \tan(\theta) = 1 \]

Answer 10

but how is the answer b.. they completely ignored the cos(theta)?

Answer 11

i have no idea, im going to ask my counselor if they could reset it or maybe if it was a mistake or something, any ways thankyou for your help