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Someone please help! \[find the range of the function f(x)= \sqrt{2x-4}-5\]
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The variable is inside a radical. No matter what number you put in for x, the smallest the root can be is 0. Then you subtract 5, so the lowest value y can have is -5. The highest is infinity.
The range Is such that it will always be equal or greater than -5
so what would be the answer?
A. y ≤ -5 B. y ≥ -5 C. y > -5 D. y ≤ 5
In interval form, the range is \([ -5, \infty) \)
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so is it Letter B
Choice B.
Thankyou, i have more questions can you please help? <3
Correct.
Pls start a new post for each one. I can help for around 15 minutes now.
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Okay Thankyou so much !<3 posting new question
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