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Mathematics 22 Online
OpenStudy (anonymous):

question coming below

OpenStudy (anonymous):

Solve \[\frac{ 5 }{ 12 } m + \frac{ 2 }{ 3 } = -\frac{ 3 }{ 4 }\] for \[m\]

OpenStudy (anonymous):

@zepdrix can you help me pls

zepdrix (zepdrix):

\[\frac{ 5 }{ 3\cdot4} m + \frac{ 2 }{ 3 } = -\frac{ 3 }{ 4 }\] If we multiply both sides by 3 and then 4, or simpy 12, it will make this a bit easier to work with.\[\large 5m+4\cdot2=-3\cdot3\] Understand what I did there?

zepdrix (zepdrix):

I cancelled some stuff out, maybe I shouldn't have skipped that step :) lol

OpenStudy (anonymous):

Its fine let me see.. @zepdrix

OpenStudy (anonymous):

the dot in the middle of 4 and 2 is that multiply or decimal?

zepdrix (zepdrix):

Multiplication :)

zepdrix (zepdrix):

I love that picture :O Ariel so pretty

OpenStudy (anonymous):

@zepdrix I drew it lol thanks

zepdrix (zepdrix):

OOO nice! :)

OpenStudy (anonymous):

I got -1.125 but as a fraction its.. -1/5

zepdrix (zepdrix):

Hmm :o ok lemme show some steps real quick, and maybe you see where it went wrong.

OpenStudy (anonymous):

that is one of my answer choices

zepdrix (zepdrix):

\[\large 12\left(\frac{5}{12} m + \frac{2}{3}\right) =\left(-\frac{3}{4}\right)12\] Multiplying both sides by 12, distributing the 12 to each term in the bracket gives us,\[\large \cancel{12}\frac{5}{\cancel{12}}m+(\cancel3\cdot4)\frac{2}{\cancel3}=\left(-\frac{3}{\cancel{4}}\right)(3\cdot\cancel{4})\] 12 is 3times4, so i wrote it that way on the other terms so we can easily cancel stuff out. This leaves us with,\[\large 5m+8=-9\]Subtracting 8 from each side,\[\large 5m=-17\]Then finally we divide each side by 5,\[\large m=-\frac{17}{5}\] Is that one of our options? :o

OpenStudy (anonymous):

no.. let me post my options

OpenStudy (anonymous):

a. \[-\frac{ 1 }{ 5 }\] b. \[-\frac{ 5 }{ 144 }\] c. \[-3\frac{ 2 }{ 5 }\] d. \[-\frac{ 85 }{ 144 }\]

OpenStudy (anonymous):

@GoldPhenoix

zepdrix (zepdrix):

Ok so the answer we came up with is clearly not a, b or d. If we rewrite our answer as a mixed number, does it match c?

OpenStudy (anonymous):

I mean @zepdrix lol

OpenStudy (anonymous):

Yes

zepdrix (zepdrix):

Yayyy \:D/

OpenStudy (anonymous):

@zepdrix Thank you so much and your time ((:

zepdrix (zepdrix):

If the multiplying by 12 thing is still really confusing, let me know :d You probably have more problems like this anyway :D practice practice

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