I am confused! I have a problem on homework: Find the limit. Use I'Hospital's Rule where appropriate. If there is a more elementary method, consider using it.
limit as x goes to 0+ of lnx/x

Question

I am confused!  I have a problem on homework:  Find the limit.  Use I'Hospital's Rule where appropriate.  If there is a more elementary method, consider using it.  
limit as x goes to 0+ of lnx/x

dumbcow · Answer

wait sorry that doesnt work

dumbcow · Answer

l'hopitals doesn't give correct answer because 2-sided limit doesnt exist

answer is neg infinity

anonymous · Answer

how do you get negative infinity?

dumbcow · Answer

only thing i can think of is go old school and plug in small x values and show it diverges to neg infinity

anonymous · Answer

okay thank you!  what about the limit as x goes to 0 of (e^x) -1 -x / x^2

anonymous · Answer

with direct substitution you get 0/0

anonymous · Answer

so then using Hospitals Rule...... what do you do?

dumbcow · Answer

take derivatives of top/bottom

--> (e^x -1)/ 2x

you still get 0/0

do it again

--> e^x / 2

you get 1/2