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What is the simplified form of:
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NO
\[\frac{ x^2 -64 }{ x^2 - 16x + 64 }\]
\[\frac{ X-8 }{ X+8 }\]
And how did you get that?.-.
@Mertsj
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Can you factor?
Put both into factors?
yes
(x - 8)(x+ 8) ----------- (x - 8)(x - 8) ?
Now cancel the common factor x-8. What remains is your answer.
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Wait I have it backwards its \[\frac{ x+8 }{ x-8 }\] \[\frac{ x ^{2} - 64}{ x ^{2}-16x + 64} = \frac{ (x - 8) (x + 8) }{ (x - 8) (x - 8) }\]
(x + 8) ------ correct? (x - 8)
Yes, mikeyy, you are correct.
Good job.
Thank you, Mertsj (:
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yw
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