Determine convergence or divergence:
1/(Ln(n)^(Ln(n)

Question

Determine convergence or divergence:
1/(Ln(n)^(Ln(n)

psymon · Answer

Now that one looks a little funky, I do say.

psymon · Answer

Is it (ln(n))^(ln(n)) or (ln(n)^(ln(n))). Just making sure.

anonymous · Answer

its natural log of (n) raised to the natural log of (n)

psymon · Answer

Okay, gotcha. Nasty. Yeah, not that it'd do much, but maybe moving itto the numerator and making the power become a -ln(n). Not that itll do much, butits what Im trying to stare at as I start

anonymous · Answer

ok

psymon · Answer

To bad the limit of it can't just be non-zero, that way we can just say diverge by nth term test, lol.

anonymous · Answer

ha

psymon · Answer

The best bet I could give is to know that 1/n diverges. 1/n Im not sure you could say is a comparison per se, but you have an idea where it's values are going to be for n. From there, I would see if your function is higher or lower for all n.

anonymous · Answer

alright..this one just baffles me..

psymon · Answer

Cant say Ive seen a problem like that to be honest. I would love to just e both sides, but there is no "both sides"

anonymous · Answer

im just gonna have to ask my professor about that one...

anonymous · Answer

im having trouble with another problem...ill close this and post it

psymon · Answer

ALrighty, cool.