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Mathematics 15 Online
OpenStudy (anonymous):

Solve & graph: 3x+5<6x-1 Ok, so the answer is 2. I got that. My problem is that you have to solve it a certain way in order to graph it properly, but I’m not sure which way I should solve it. I solved it this way: 3x+5<6x-1 -3x 5<3x-1 +1 6<3x /3 2) or (<) sign if you divide negatives. So while the numerical answer remains the same, the graphing gets messed up.

OpenStudy (anonymous):

Anyway, I just want to know if there’s some kind of rule for solving problems like this. I figured because 3x is the smaller number you’d start by subtracting that and adding it to 6x (that, and I try to prevent getting negatives if I can), but apparently not. =/ Thanks in advance.

OpenStudy (anonymous):

If you subtract the 6x first the answer would be -2, not 2

HanAkoSolo (jamierox4ev3r):

3x+5<6x-1 -3x -3x --------- 5<3x-1 +1 +1 -------- 6<3x /3 /3 ----- x=2

HanAkoSolo (jamierox4ev3r):

i men x>2

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