Rewrite with no negative exponents $$\frac{ x^5 }{ x^-2 }$$ the -2 is an exponent

Question

anonymous · Answer

@bahrom7893 Hello, i posted my second question

bahrom7893 · Answer

$$\frac{a}{b^c} = a*b^{-c}$$

bahrom7893 · Answer

No exceptions. So in your case:
$$\frac{x^5}{x^{-2}} = x^5 * x^{-(-2)} = x^5*x^2=x^{5+2}=x^7$$

anonymous · Answer

I dont get it

bahrom7893 · Answer

I'll be right back, just going to go eat real quick, didn't have dinner yet.

anonymous · Answer

Okay ill be waiti

bahrom7893 · Answer

Back.

anonymous · Answer

Okay

bahrom7893 · Answer

Okay, so here's the rule, whenever you have a fraction as follows:
$$fraction =\frac{numerator}{denominator}$$You can rewrite it this way:$$fraction=numerator*(denominator)^{-1}$$It's a rule, memorize that.

bahrom7893 · Answer

So in your case, you have:
$$\frac{x^{5}}{x^{-2}} = x^{5}*(x^{-2})^{-1}$$

bahrom7893 · Answer

So far so good?

anonymous · Answer

yes just dont really get it still

bahrom7893 · Answer

http://www.dummies.com/how-to/content/working-with-negative-exponents.html Read through this before we continue. I really am not sure how to explain this. Can't come up with an analogy :/

anonymous · Answer

Im sorry, ive read it and still dont understand this type of material?

bahrom7893 · Answer

All I can say is read it again, paying more attention.

anonymous · Answer

@thivitaa 
 hey this question

thivitaa · Answer

bah has already gave u the ans...i think..

anonymous · Answer

no he didnt

anonymous · Answer

he gave me the step right before the answer but i dont know how to finish it