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sin 4u = 2 sin 2u cos 2u verify the identity
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@Mertsj @mebs
@satellite73
You have the identity sin 2x = 2sin x cos x
Let x = 2u Then 2x = 4u Make the substitutions
so it would be sin2x=2sinxcosx?
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and then from there what do i have to do just solve?
so we have an identity \[\sin(A+B) = sinAcosB + cosAsinB\] we have sin(4u) = sin(2u + 2u) can you substitute and sovle?
to solve would just leave me with cosx rigth ? @Mertsj @mebs
no it wouldn't ... here it would look like this sin(2u + 2u) = sin2ucos2u + sin2ucos2u add them and you prove the identity.. its self explanatory.
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