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Mathematics 18 Online
OpenStudy (anonymous):

You toss 3 coins. What is the probability that you get exactly 3 heads, given that you get at least one head? A tree diagram will help you to answer this question.

OpenStudy (anonymous):

@mathmate

OpenStudy (anonymous):

You already know that one of the three coins is going to be heads. So, what you're really looking for is the probability that the other two coins are both heads. What is the probability of flipping two coins and they are both heads?

OpenStudy (anonymous):

so... HHT would be one?

OpenStudy (anonymous):

Possible let's say HHH and TTT but it does not have one head. Understand ?

OpenStudy (anonymous):

i understand why TTT isnt but HHH does

OpenStudy (anonymous):

@music101 It's simpler than you're making it. The first coin is irrelevant because we know it's heads. So make this into a new problem: If we flip two coins, what is the probability that both coins are heads?

OpenStudy (anonymous):

2/2 ?

OpenStudy (anonymous):

or 1/4

OpenStudy (anonymous):

Right, 1/4, since each coin has a 1/2 probability of being heads and there are two coins, so: (1/2)(1/2)=1/4

OpenStudy (anonymous):

Me personal I will say 3/7 . Because their are 7 situations with probably one head and 3 two.

OpenStudy (anonymous):

so then..

OpenStudy (anonymous):

so theyre asking u to find the probability that you actually get TWO heads??

OpenStudy (anonymous):

@vinnv226

OpenStudy (anonymous):

@music101 Right. You're flipping three coins. The first coin is definitely heads, so we can put it aside and look at the two remaining coins. There is a 1/4 probability of these other coins both being heads.

OpenStudy (anonymous):

oh cuz its 1/2* 1/2?

OpenStudy (anonymous):

so the answer is 1/4?

OpenStudy (anonymous):

Yes, I believe thats correct. You could check it using another method, like tree diagrams

OpenStudy (anonymous):

I have no clue how to do that that's why I asked this in the first place :(

OpenStudy (anonymous):

how would u do that??

OpenStudy (anonymous):

I gonna submit 1/4

OpenStudy (mathmate):

There are eight outcomes when you throw a coin 3 times, one of which is TTT, and another is HHH. "Given that you have at least one head" means you would ignore the case TTT, that leaves you with 7 outcomes. So P(HHH)=1/7.

OpenStudy (anonymous):

:( I already submitted 1/4 :( :( this sucks!

OpenStudy (anonymous):

We've all given a lot of different answers here, but I don't think any of us have drawn the tree diagram yet...maybe we could agree on an answer if we do

OpenStudy (anonymous):

ok.. but right now I need help w/ the other question

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