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What is the 7th term of the geometric sequence where a1 = 1,024 and a4 = -16?
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well 1st the formula for a term in a geometric series is \[a_{n} = a_{1} \times r^{n - 1}\] 1st you need to find the common ratio before finding the 7th term so use what you know \[-16 = 1024 \times r^{4 -1}\] solve for r. when you have it, go to the formula and find the 7th term with n = 7
r=-1/4?
thats correct... so just evaluate \[a_{7} = 1024 \times (\frac{-1}{4})^{7 -1}\]
you should get a positive answer
so it is .25
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thats right
Thankyou that helped alot
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