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Mathematics 6 Online
OpenStudy (anonymous):

I need help with this. I have tried using the formula they gave me in my lesson, but it came out with the wrong answer. Can someone help me?

OpenStudy (anonymous):

OpenStudy (phi):

what formula did you use ?

OpenStudy (anonymous):

(n-2) times 180 degrees divided by n

OpenStudy (campbell_st):

well you are looking at an irregular hexagon the angle sum is Angle Sum = 180 x ( n - 2) where n = 6 so the angle sum is 720 degrees so using what is shown in the question you have \[720 = 138 + 128 + 10x -4 + 10x -4 + 5x + 8 + 5x + 8\] collect the like terms and then solve for x.

OpenStudy (phi):

yes, so where did you go off the tracks? 6-4 = 4 and 4*180= 720 degrees the sum of the internal angles is 720 .

OpenStudy (anonymous):

I thought the numbers in the parentheses was the number of sides minus 2.

OpenStudy (phi):

it is. I count 6 sides. Don't you ?

OpenStudy (phi):

I just notice you posted (n-2) times 180 degrees divided by n the divide by n gives you the internal angle if you have a *regular* figure. (where all the angles are the same) in this problem, all you know is that the sum of the internal angles (which are different) add up to (n-2)*180 = (6-4)*180= 4*180= 720

OpenStudy (phi):

For example, if you have a triangle with 3 sides, the sum of the internal angles is (3-2)*180= 1*180= 180 if you have an *equilateral triangle* (where all the internal angles are the same) then the internal angle is (n-2)*180/n = (3-2)*180/3 = 180/3 = 60 in this problem, all we know is the sum of internal angles add up to 720. But the internal angles are not all the same

OpenStudy (phi):

so do what campbell posted, add up the internal angles and set that sum equal to 720

OpenStudy (anonymous):

Alright. I'll do that.

OpenStudy (anonymous):

274 + 30x = 720

OpenStudy (campbell_st):

now just solve for x

OpenStudy (anonymous):

14.8?

OpenStudy (anonymous):

So it's 14.8? Or is there more to the problem than that?

OpenStudy (campbell_st):

that seems to be close \[x = \frac{720 - 272}{30}\]

OpenStudy (anonymous):

I did that and I got 14.9?

OpenStudy (campbell_st):

oops slight typo its \[x = \frac{720 - 274}{30}\]

OpenStudy (campbell_st):

but rounded to 1 decimal place its still 14.9 degrees

OpenStudy (anonymous):

So is that what it is?

OpenStudy (campbell_st):

yep... thats the size of x, I don't know what the question was... if you need to find the angles then its 10*14.9 -4 and 5 * 14.9 + 8 and I don't know how accurate you answer needs to be... as in how many decimal places.

OpenStudy (anonymous):

I had to find the measure angle of F. Sorry. I should have posted that to begin with

OpenStudy (campbell_st):

so F = 10x - 4 F = 10*(14.867) - 4 just depends on the level of accuracy.. but the method above is correct.

OpenStudy (phi):

you are on the right track but I get 30x +270= 720 (not 274)

OpenStudy (anonymous):

So I do that?

OpenStudy (phi):

if you simplify 720=134+128+10x−4+10x−4+5x+8+5x+8 you should get 720 = 262 +30x + 8 or 720 = 270 + 30x or 30x = (720-270) 30 x= 450 can you find x and then the angle you want ?

OpenStudy (anonymous):

I have to find what Angle F equals.

OpenStudy (phi):

30 x= 450 can you find x and then the angle you want ?

OpenStudy (phi):

to find x, divide both sides of the equation by 30

OpenStudy (anonymous):

For that, I got 15.

OpenStudy (phi):

ok now angle F = 10*x - 4 what is 10 times 15 then take away 4 ?

OpenStudy (anonymous):

146

OpenStudy (phi):

yes

OpenStudy (anonymous):

That's the anwer?

OpenStudy (phi):

yes. Think over what you did... you found x to be 15 then you see angle F= 10*x -4 you replaced x with its value of 15 and simplified to get angle F= 10*15 -4 = 150-4 = 146 degrees all done

OpenStudy (anonymous):

Thank you so much.

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