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When 7.0 mol Al react with 8.5 mol HCl, what is the limiting reactant and how many moles of AlCl3 can be formed? 2 Al + 6 HCl “yields”/ 2 AlCl3 + 3 H2 Al is the limiting reactant, 7.0 mol AlCl3 can be formed HCl is the limiting reactant, 2.8 mol AlCl3 can be formed Al is the limiting reactant, 3.5 mol AlCl3 can be formed HCl is the limiting reactant, 8.5 mol AlCl3 can be formed
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divide the amount of moles of each individual species by it's own coefficient in the balanced equation: moles/coefficient= normalized moles which ever one has the least amount is the limiting reactant.
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