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Mathematics 16 Online
OpenStudy (anonymous):

what is the surface area of the right cone below?

OpenStudy (anonymous):

not 14

OpenStudy (anonymous):

The surface area of a cone is SA = π*R^2 + π*R*L I can not see the picture...

OpenStudy (anonymous):

refresh the URL, you will see the pic

OpenStudy (anonymous):

OpenStudy (anonymous):

Better.

OpenStudy (anonymous):

So using the formula π*R^2 + π*R*L we get π*64 + π*8*14

OpenStudy (anonymous):

Which is 552.9 or 176 π

OpenStudy (anonymous):

i don't see non of those answers in my answer choice.

OpenStudy (anonymous):

What answers are in your choice?

OpenStudy (anonymous):

A. 184pi Units2 B. 304pi Units2 C. 248pi Units2 D. 496pi Units2

OpenStudy (anonymous):

If we find the missing foot we can use the formula SA = 1/3 * pi * R^2 * H H being the vertical leg of the triangle

OpenStudy (anonymous):

So using the pathogen theorem we get 14^2-8^2 = b^2 b = sqrt (196-64) b = 11.4891

OpenStudy (anonymous):

Plugging that back into the 2nd formula we get 1/3 * pi * 8^2 * 11.4891 which comes out to around 245 pi It is probably C, Sorry I didn't get the exact answer.

OpenStudy (anonymous):

Sorry I don't know exactly.

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