Question

simplify the rational expression state any excluded valus

Answer 1

\[\frac{ x-2 }{ x^2+3x-10 }\]

Answer 2

It doesn't look like latex commands are interpreted.
Anyway, excluded values are those that make the denominator zero, which creates holes or vertical asymptotes.

Answer 3

refresh @mathmate it looks fine for me

Answer 4

you need to factor the denominator, then something will cancel with the top
and you need to make a note of any information that cancels away
so say you get (x-2)(x+5) on the bottom and the x-2 cancels with the top
then you need to make a note saying that these things are equal to each other as long as x cant be 2
note on the first equation x cant be 2

Answer 5

@zzr0ck3r I updated my IE and it now works properly. Thanks.

For @cupcake918 , you need to factorize the denominator. If you exclude values that make each of those factors zero, then you can cancel common factors between the numerator and denominator.

Answer 6

i dont understand how to do that

Answer 7

\[\frac{ x-2 }{ x^2+3x-10 }\]
\[=\frac{ x-2 }{ (x-2)(x+5) }\]
\[= \frac{ 1 }{ x+5 }\]

The excluded value is when x = 2 since the original expression would have been undefined at x = 2 but the reduced expression would have has

Answer 8

sorry the reduced expression would have a value of 1/7 at x = 2. Thus x =2 is an exception to when \[\frac{ x-2 }{ x^2+3x-10 }=\frac{ 1 }{ x+5 }\].
Sometimes this is written as
\[\frac{ x-2 }{ x^2+3x-10 }=\frac{ 1 }{ x+5 }\]
\[x \neq2\]