Question

Compare the two graphs and describe their relationship.
f(x) = sin(x)
g(x) = sin(x – )

Answer 1

-x or is there supposed to be something after x - ?

Answer 2

x-pi XD opps

Answer 3

When I graphed them, they were like.. really close to the x axis.
Like really close. Is that all I have to say?

Answer 4

Somehow I doubt that, haha.

Answer 5

Me too. I don't think my graphing calculator did it right, though, because the lines were straight,

Answer 6

No wonder my logic wasnt making sense with my calculator, I put in cosine -_-. Okay, this is a phase shift problem.

Answer 7

So you have a common graph form of Asin(bx - C). In this case b is just 1 and c = pi (not negative pi). So a phase shift tells you where you should start your graph. To find the phase shift, you do c/b. In this case, c/b is simply pi. So pi is where your graph starts at. SInce that is the only sort of change in your graph from a regular sin graph, the sin graph will continue in the exact same way, just from pi instead.

Answer 8

So overall, when you have a form of Asin(bx-c) Just to give you all the main graphing rules. abs value of A = amplitude. 2pi/b = period (if its sin or cos), and c/b is the phase shift, or simply where your graph starts at.

Answer 9

......I'm confused now.

Answer 10

Well, basically it's just asking to compare the two graphs. Sowe know what a basic sinx graph looks like, correct?

Answer 11

No...DX

Answer 12

Ah x_x Alright, guess thats not needed really. Well, lets just try and see if I can explain the basic form of a trig graph. The basic form is Asin(bx - c). Now just like in a regular algebraic graph, like x^2 being shifted by making it (x-2)^2, it works the same way with trig functions, just there are differences

Answer 13

So when you have a sin graph lets say, they come in the form Asin(bx-c) (even if there is no a b or c, it is still technically of that form. The A in that form (which is 1 with us since theres no number there), is the maximum and minimum point of the graph. So ifI had 3sinx, I would go as high as y = 3 and as low as y = -3. Kinda make sense so far?

Answer 14

Oh. I actually did know that then XDDDDD

Answer 15

Haha, awesome. Now to continue on. Sin and cos both have a period of 2pi normally. Now just as the max or min height of the graph may change, so could the period. The period is determined by 2pi/b. In our case, b is just 1, since there is no coefficient in front of x. We kinda got that?

Answer 16

Yeah.

Answer 17

Awesome. So the last piece is whats called a phase shift. The phase shift tells you how much your graph gets moved left or right. This is determined by taking c/b. In this case, cis just pi and b is 1, therefore our graph is shifted by pi units. Ill see if I can draw.

Answer 18

That makes sense

Answer 19

Awesome :P But yeah, just a visual. The normal starting point of a sin graph is (0,0). Instead, I just started at pi and did the normal curvy whatever xD