Simplify h(a+3)-h(3)/a when h(x)=x^2+4x+5

Question

anonymous · Answer

I don't know what to do...

psymon · Answer

Ouch to that one. Well, you would start off with h(a+3). You need to plug (a+3) into every x you have in your function and simplify. If we can get that done okay we can keep going. But essentially, when it says f(__), whatever is in there is what gets replaced into every single variable in your equation.

anonymous · Answer

not nearly as bad as it looks
what is $f(3)$?

anonymous · Answer

So I simplified it down to a^2+6x+4a/a but I think that it is wrong, because you cannot divide it by a still.

anonymous · Answer

or rather $h(3)$ ?

anonymous · Answer

you have no $x$ in this, so there is a mistake somewhere

anonymous · Answer

$h(3)=9+12+5=26$ right?

anonymous · Answer

Wait, lol, I think that it is a^2+6a+4a/a

anonymous · Answer

well i don't know if that is right, but if it is, divide by $a$ and get $a+10$ 
lets try it

anonymous · Answer

$h(3)=26$
$$h(a+3)=(a+3)^2+4(a+3)+5\=a^2+6a+9+4a+12+5=a^2+10a+26$$

anonymous · Answer

so $h(a+3)-h(3)=a^2+10a$

anonymous · Answer

divide by each term by  $a$ and get $a+10$

anonymous · Answer

I see it... Lol I make the stupid mistakes always... That is what always gets me...

anonymous · Answer

i think you just forgot to combine like terms

anonymous · Answer

Nah, I'm just hardcore derping. It is the first day back to school, and the teacher gave us an assignment and said that there will be a quiz tomorrow, and I think that I am scared to take it tomorrow.