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Mathematics 8 Online
OpenStudy (anonymous):

(x-1/y)/(x/y) = ?

OpenStudy (tkhunny):

Which do you mean? \(((x-1)/y)/(x/y)\;or\;(x-(1/y))(x/y)\)

OpenStudy (anonymous):

Okay so we basically just multiply by the reciprocal: \[(\frac{ x-1 }{ y })(\frac{ y }{ x })\] Which further gives us: \[\frac{ y(x-1) }{ xy }\] This can be further simplified into: \[\frac{ xy-y }{ xy }\] After that we can simply cancel out like terms: \[\frac{ x-1 }{ x }\] We cannot cancel out the x's because we do not have a "perfect three" where all three terms (the x, the -1, and the x in the denominator) have like terms.

OpenStudy (anonymous):

Of course, this is assuming you meant ((x−1)/y)/(x/y)

OpenStudy (anonymous):

its (x-(1/y))/(x/y). sorry for the confusion

OpenStudy (tkhunny):

That IS what you originally wrote, but so many write incorrectly that it is hard to know. Thanks for the clarification.

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