Question

2^5/2-2^3/2

doesnt it equal 2^2

Answer 1

or just 2?

Answer 2

\[\frac{2^5}{2^1}- \frac{2^3}{2^1}=2^{5-1}-2^{3-1}=2^4-2^2=16-4=12\]

Answer 3

No!!! @mathstudent55
Only like terms can be added. Like terms have the same exponents.

Answer 4

\[2^{5/2}-2^{3/2}\]

answers are 2^1/2,2,2^3/2,2^5/3,2^2

it says the correct answers is 2^3/2

Answer 5

i dont get how this is possible, here is the test it is the first in college level algebra http://media.collegeboard.com/digitalServices/pdf/accuplacer/accuplacer-sample-questions-for-students.pdf

Answer 6

*level mathmatics

Answer 7

@Mertsj
Wow. Midway through the problem I forgot it was a subtraction instead of a division. I still think the question is using fractional exponents, though.

Answer 8

it is fractional exponents

Answer 9

\[2^{\frac{5}{2}}=\sqrt{2^5}=\sqrt{32}=4\sqrt{2}\]

Answer 10

\[2^{\frac{3}{2}}=\sqrt{2^3}=\sqrt{8}=2\sqrt{2}\]

Answer 11

\[4\sqrt{2}-2\sqrt{2}=2\sqrt{2}\]

Answer 12

i really dont understand how they say the correct answer is \[2^{3/2}\]

Answer 13

\[2\sqrt{2}=2^1(2)^{\frac{1}{2}}=2^{1+\frac{1}{2}}=2^{\frac{3}{2}}\]

Answer 14

Here is another way to think of it:

Answer 15

where did you get? [2^{1}\]? sorr this is so confusing

Answer 16

\[2^{\frac{5}{2}}-2^{\frac{3}{2}}=2^{\frac{3}{2}}(2^{\frac{2}{2}}-1)=2^{\frac{3}{2}}(2-1)=2^{\frac{3}{2}}(1)=2^{\frac{3}{2}}\]

Answer 17

2 is the same as 2^1

Answer 18

\( \large{ 2^{\frac{5}{2}}-2^{\frac{3}{2} } }\)

\( = 2 \times 2^{\frac{3}{2}} - 2^{\frac{3}{2}} \)

\(= 2^{\frac{3}{2}} (2 - 1) \)

\(= 2^{\frac{3}{2}} \)