John is making himself a lunch. He has three different soups to choose from, four kinds of soda, and three different kinds of fruit. How many different lunches can he prepare today?
a.28
b.36
c.40
d.48

I need explanation!

Question

John is making himself a lunch. He has three different soups to choose from, four kinds of soda, and three different kinds of fruit. How many different lunches can he prepare today?
a.28
b.36
c.40
d.48

I need explanation!

anonymous · Answer

B

3*4*3 Bruh

uri · Answer

I need explanation.

uri · Answer

@satellite73 @mathstudent55

anonymous · Answer

counting principle all the way

uri · Answer

I totally understand what you just said..

primeralph · Answer

Just count all the bases, you get what I mean. The answer is 3*4*3.

anonymous · Answer

if there are $n$ ways to do one task, and $m$ ways to do another, then the total number of ways they can be done together is $n\times m$

anonymous · Answer

so if there are 3 ways to do one thing and 4 to do another, total number of ways to do them both is $3\times 4=12$
this is the COUNTING PRINCIPLE

uri · Answer

Get it till here,Next?

anonymous · Answer

which of course extends to more than just two things

uri · Answer

I got it,Thanks. (:

anonymous · Answer

if there are $n_1, n_2, n_3, ...,n_p$ ways to do respectively $1,2,3,...,p$ tasks, then the number of ways to do them combined is $$n_1\times  n_2\times n_3\times ...\times n_p $$

primeralph · Answer

Shall we go skinny dipping now?|dw:1375238089964:dw|