Based on the graph, it can be concluded that the isotope which is most likely to be found with 6.25% of its original amount in 6 billion years is Uranium-238 Thorium-235 Potassium-40 Rubidium-87
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Potassium-40. Do you know why? @watermelon14
no i don't know why I thought it was the first one. Why is is potassium-40 and thank very much!
You could use the half-life formula or JUST THINK ABOUT IT. The half life of Potassium-40 from what it looks like off the graph is like 1-1.5 bill years. If it halfs in 1-1.5 billion years, then there is 50% left. In another 1-1.5 billion years there will be 25%. If we do that 2 more times, we get 12.5% and then 6.25%. Our estimate is about 1-1.5 billion years hence repeating that about 4 times we get around 4-6 billion years for it to get to 6.25%. The rest obviously can't be an option because each of the other choices either reaches only 50% of its original amount in more than 6 billion years. The other option thats comes closest is U-238 which seems to have a half life of about 4 billion years. This means that at 8 billion years, it will be around at 25% the original amount. From this we can conclude the clear choice would have to be Potassium-40 since it comes the closest to remaining at 6.25% its original amount after approximately 6 billion years. @watermelon14
You get it?
yes! Thanks very much!!!!!! :3
Or use the formula:\[\bf A=A_0(0.5)^{\frac{t}{h}}\]If A = 6.25% then:\[\bf 0.0625=0.5^{\frac{6 \ BY}{h}} \implies \log(0.0625) = \frac{6 \ BY}{h}\log(0.5)\]\[\bf \implies h = half-life = \frac{6 \ BY(\log(0.5))}{\log(0.0625)} =1.5 \ BY\]This means that the substance has a half life of 1.5 billion years much like our estimate. Hence the only once it could be looking at the graph is Potassium-40. @watermelon14
and the 'BY' is billion years, and the "half - life" is simply "half life" not "half minus life". lol. @watermelon14 now i g2g. good luck.
okay!!! Thankssss!!!!!!!!!!!!
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