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Mathematics 18 Online
OpenStudy (anonymous):

Please Help ! The domain of y = cot x is given by (Attachment)

OpenStudy (anonymous):

OpenStudy (anonymous):

Please Someone Help Me ! I'd be so grateful

OpenStudy (primeralph):

Just try any n*pi and see if the answer is defined.

OpenStudy (tkhunny):

\(\cot(x) = \dfrac{\cos(x)}{\sin(x)}\). This is defined everywhere except where \(\sin(x) = 0\)

OpenStudy (anonymous):

So its False ?

OpenStudy (primeralph):

How do we say this? It's not not not not true.

OpenStudy (tkhunny):

Where is \(\sin(x) = 0\)?

OpenStudy (tkhunny):

Confused by what? Answer the question.

OpenStudy (zzr0ck3r):

sin(x) cant be equal to zero because then you would be dividing by 0 cot=cos/sin sin(x) = 0 when x = n*pi where n is natural so we must leave those out

OpenStudy (tkhunny):

What? sin(x) certainly can be zero. Wherever sin(x) = 0, the cotangent function fails to exist. This is the nature of the Domain of the cotangent function. This is the whole point of the question. I ask again, where is \(\sin(x) = 0\)?

OpenStudy (anonymous):

Oh okay, thank you for that explanation @zzr0ck3r I understand it now (: Your awesome !

OpenStudy (anonymous):

when x = integral multiples of Pi => x = n*pi

OpenStudy (anonymous):

@tkhunny

OpenStudy (anonymous):

I got it right it was TRUE !

OpenStudy (tkhunny):

Yea! Good work.

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