Please Help ! The domain of y = cot x is given by (Attachment)
Please Someone Help Me ! I'd be so grateful
Just try any n*pi and see if the answer is defined.
\(\cot(x) = \dfrac{\cos(x)}{\sin(x)}\). This is defined everywhere except where \(\sin(x) = 0\)
So its False ?
How do we say this? It's not not not not true.
Where is \(\sin(x) = 0\)?
Confused by what? Answer the question.
sin(x) cant be equal to zero because then you would be dividing by 0 cot=cos/sin sin(x) = 0 when x = n*pi where n is natural so we must leave those out
What? sin(x) certainly can be zero. Wherever sin(x) = 0, the cotangent function fails to exist. This is the nature of the Domain of the cotangent function. This is the whole point of the question. I ask again, where is \(\sin(x) = 0\)?
Oh okay, thank you for that explanation @zzr0ck3r I understand it now (: Your awesome !
when x = integral multiples of Pi => x = n*pi
@tkhunny
I got it right it was TRUE !
Yea! Good work.
Join our real-time social learning platform and learn together with your friends!