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Mathematics 15 Online
OpenStudy (anonymous):

3^x+4=7^x-1

OpenStudy (anonymous):

my guess is this is \[\large 3^{x+4}=7^{x-1}\]am i right?

OpenStudy (anonymous):

It's an exponent

OpenStudy (anonymous):

is it the question i wrote?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

then start with \[\large (x+4)\ln(3)=(x-1)\ln(7)\] then do a raft of algebra to solve for \(x\)

OpenStudy (anonymous):

Do you mind helping me a little bit more? I have just started to do these and don't understand how they work. I've watched videos but still don't get it.

OpenStudy (anonymous):

no i don't mind first step is to write what i wrote above \[\large (x+4)\ln(3)=(x-1)\ln(7)\] now \(\ln(3)\) and \(\ln(7)\) are just numbers, so to solve for \(x\) we have to multiply out first to get rid of the parentheses

OpenStudy (anonymous):

we get \[x\times \ln(3)+4\ln(3)=x\times \ln(7)-\ln(7)\] when you remove the parentheses okay so far

OpenStudy (anonymous):

Yes I understand.

OpenStudy (anonymous):

ok now as usual to solve for \(x\) you need everything with an \(x\) on one side of the equal sign, everything else on the other it doesn't really matter which side you put it on, but i will subtract \(x\times \ln(7)\) from both sides to get \[x\ln(3)-x\ln(7)+4\ln(3)=-\ln(7)\]

OpenStudy (anonymous):

then the part without an \(x\) should go on the other side, subtracting \(4\ln(3)\) from both sides gives \[x\ln(3)-x\ln(7)=-\ln(7)-4\ln(3)\]

OpenStudy (anonymous):

ok to that step? only two more

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

ok now we factor the \(x\) out of the left so we can figure out what to divide by \[(\ln(3)-\ln(7))x=-\ln(7)-4\ln(3)\]

OpenStudy (anonymous):

then divide to get \[x=\frac{-\ln(7)-4\ln(3)}{\ln(3)-\ln(7)}\]

OpenStudy (anonymous):

there are lots of other ways to write this so if you have a different answer in the book for example, don't get confused

OpenStudy (anonymous):

for example we could make it have less minus signs by writing \[x=\frac{\ln(7)+4\ln(3)}{\ln(7)-\ln(3)}\]

OpenStudy (anonymous):

Alrighty and I do online and well you don't get much information about the problems or a book but thank you for your help:)

OpenStudy (anonymous):

hope it was more or less clear all the steps are there one at a time, so if you copy them you will have them to mimic for another such problem yw

OpenStudy (anonymous):

Okay thank you.

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