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The weight of a liquid varies directly as its volume V. If the weight of the liquid in a cubical container 5cm on a side is 375g, find weight of the liquid in a cubical container 4 cm on a side?
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Assuming the density of the liquid remains constant. let D = density, M = mass and V = volume. \[D = \frac{ M }{ V } =\frac{ 375g }{ 5*5*5 } = \frac{ M_2 }{ 4*4*4 }\]
cross multiplying will get you the answer
I came up with 192 g. is that right? im not sure
it is right
thank you....I was having difficulties solving this one
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glad i could help :)
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