Question

I don't know how to do any of the steps for this problem. Can someone please help me?

Find the slope-intercept equation of the line with the following properties:
Parallel to the line y=−5; containing the point (4,8).

Answer 1

the equation will have the form
y=mx+b where m is slope and b is the y intercept
parallel means it will have the same slope
so we have
y = -5x+b
now we need to solve for b
so use the point they gave you (4,8)
so
when y = 8, x =4
plug this in
y=-5x+b becomes
8=-5*4+b
solve for b and tell me what you have.

Answer 2

but y=-5, not m. I thought the same thing and the professor said it wasn't right

Answer 3

y=8, both are horizontal lines

Answer 4

but how do you come up with that?

Answer 5

ahh its y = -5 not y = -5x
sorry
so it will be y = 8

Answer 6

but how do I come to that? I don't understand this and it was due by yesterday.

Answer 7

y=-5 has 0 slope
so we know the equation will have 0 slope
and pass through (4,8) only one line does this
y=8

Answer 8

from the form of the equation y = -5. when y = a constant, it's a horizontal line. no matter what x is, y is always -5 for this line.
A horizontal line has a slope of 0. so in y=mx+b, m = 0. thus y = b. in your problem the line parallel to y = -5 goes through the point (

yeah, rendering all this pointless

Answer 9

Ah. Ok. Thank you very much! :)